Purpose:
The
primary purpose of this experiment is to use a simple apparatus to determine
the spacing of the lines within a compact disk. This experiment will explore
the properties of diffraction gradients using everyday items and a laser of
known wavelength. The laser will be used to measure the spacing of the lines by
using the relationship learned of light diffraction. Once the spacing have been
determined, the obtained results will be compared to the factory requirements
of 1600nm and evaluated. In addition to the CD, a DVD will also be evaluated
and its spacing will also be compared to the factory specifications of 740nm.
Procedure:
First,
the following supplies were gathered: CD, DVD, piece of paper, meter stick and
a laser. The paper was first taken and a hole was placed in the middle of it. Once
that was done, the laser was placed on the table so that the beam would strike
through the hole created. On the opposite side of the paper, the CD was placed
so that the beam would reflect off and bounce diffractively back at the paper.
Once this was completed, the
spacing of the dots were measured and recorded. The length from the CD to the
paper was also recorded to be used in later calculations. This entire process
was then repeated with the DVD to determine the differences.
Data Analysis:
CD:
The
following data chart displays the raw recorded data for the CD measurements
with x representing the distance to the first maxima, l indicating the distance
from the paper to the CD, and lambda representing the wavelength of the laser:
Trial
|
x(cm)
|
l(cm)
|
λ(nm)
|
1
|
11.5 ± .5
|
24.3 ± .5
|
633
|
2
|
14.8 ± .5
|
32.4 ± .5
|
633
|
3
|
16 ± .5
|
34.8 ± .5
|
633
|
The following sample calculation
represents the work done to determine the spacing between each line for the CD:
Sinθ = λ/a = x/(x2+l2)1/2
a
= λ(x2+l2)1/2/x
a
= (633nm)(11.5cm2+24.3cm2)1/2/11.5cm
a
= 1480nm
The proceeding table includes the
calculated spacing for all three trials:
Trial
|
Spacing(nm)
|
1
|
1480
|
2
|
1520
|
3
|
1520
|
DVD:
Unfortunately,
the DVD experiment was only done once due to time restraints. The following
table represents the raw data achieved for the DVD, again the same values
represent the same quantities as the CD observations:
Trial
|
x(cm)
|
l(cm)
|
λ(nm)
|
1
|
9.1 ±
.5
|
5.5 ±
.5
|
633
|
Using the same calculations as
for the CD, the spacing for the DVD is as followed:
Trial
|
Spacing(nm)
|
1
|
739 ±
89
|
Conclusion:
After
completing all necessary calculations, the spacing for both the CD and DVD were
found. The computed spacing of the CD were found to be 1480 nm and 1520 nm. When
these values were compared to the factory standard of 1600nm, the range of
errors ranged from 5.0% to 7.5%. Considering the small amounts of distances
being evaluated, these numbers are rather large. It would be recommended that
the factory consider the way their CDs are produced to ensure that the
standards are more closely achieved. As for the DVD, the spacing was found to
be close to 740nm. When comparing this to the standard of 760nm, the error of
2.6% is not as far off as from the CD. It would not be recommended to the
factory to consider the manufacturing process of their DVDs since the error is
relatively small.